AtCoder Beginner Contest 002

Submission #7065898

Source codeソースコード

#include <stdio.h>
#include <iostream>
#include <ios>
#include <iomanip>
#include <algorithm>
#include <sstream>
#include <complex>
#include <vector>
#include <list>
#include <queue>
#include <deque>
#include <stack>
#include <set>
#include <map>
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cstring>
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef string str;
typedef std::pair<ll,ll> pl;
typedef std::map<string, ll> msl;
typedef std::map<char, ll> mcl;
typedef std::map<ll, ll> mll;
typedef std::vector<ll> vl;
typedef std::vector<pl> vpl;
const ll MOD = 1e9 + 7;
const ll INF = MOD * MOD;
const long double PI = 3.14159265359;
const long double EPS = 1e-9;

ll gcd(ll m, ll n){
    ll a = max(m, n);
    ll b = min(m, n);
    while(b != 1 && b != 0){ a %= b; swap(a, b);}
    return b == 1 ? 1 : a;
}

ll lcm(ll m, ll n){ return m / gcd(m, n) * n;}

ll power_mod(ll a, ll power, ll mod){
    ll value = 1;   
    while(power != 0){
        if(power & 1) value = (value * a) % mod;
        a = (a * a) % mod;
        power = power >> 1;
    }
    return value % mod;
}

ll modinv(ll a, ll mod){
    return power_mod(a, mod - 2, mod);
}

ll power_normal(ll a, ll power){
    ll value = 1;   
    while(power != 0){
        if(power & 1) value = value * a;
        a = a * a;
        power = power >> 1;
    }
    return value;
}

ll combination(ll n, ll r){
    ll numerator = 1;
    ll denomenator = 1;
    for(ll i = 0; i < r ; i++){
        (numerator *= ll(n - i)) %= MOD;
        (denomenator *= modinv(i + 1, MOD)) %= MOD;
    }
    return (numerator * denomenator) % MOD;
}

ll bin_search_range(ll key, ll S[], ll left, ll right) {
    
    while (right >= left) {
        ll mid = left + (right - left) / 2;
        if (S[mid] >= key && S[mid - 1] < key) return mid;
        else if (S[mid - 1] >= key) right = mid - 1;
        else if (S[mid] < key) left = mid + 1;
    }
    return right + 1;
}

ll bin_search(ll key, ll A[], ll left, ll right){
    // return the index idx where A[idx] = key.
    // A[left] is start and A[right] is end.
    while(right >= left){
        ll mid = left + (right - left) / 2;
        if (A[mid] == key) return mid;
        else if (A[mid] > key) right = mid - 1;
        else if (A[mid] < key) left = mid + 1;
    }
    return -1;
}

#define rep(i, n) for(ll (i) = 0; (i) < (n) ; (i)++ )
#define For(i, a, b) for(ll (i) = (a); (i) < (b) ; (i)++ )
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
#define isUpper(c) ('a' - c > 0) 
#define toLower(c) char((c)+0x20)
#define toUpper(c) char((c)-0x20)
#define pb push_back
#define mp make_pair
#define pr(a) cout << (a)
#define prl(a) cout << (a) << endl
#define prl2(a,b) cout << (a) << " " << (b) << endl
#define prs(a) cout << (a) << " "
#define yn(condition) if ((condition)) prl("Yes"); else prl("No");
#define YN(condition) if ((condition)) prl("YES"); else prl("NO");
#define rpr(i,n,ans) rep((i),(n)) prs((ans[(i)]))
#define cpr(i,n,ans) rep((i),(n)) prl((ans[(i)]))
#define in1(a) cin >> (a)
#define in2(a,b) cin >> (a) >> (b)
#define in3(a,b,c) cin >> (a) >> (b) >> (c)
#define in4(a,b,c,d) cin >> (a) >> (b) >> (c) >> (d)
#define rin1(i,n,a) rep((i),(n)) cin >> (a[(i)])
#define rin2(i,n,a,b) rep((i),(n)) cin >> (a[(i)]) >> (b[(i)])
#define rin3(i,n,a,b,c) rep((i),(n)) cin >> (a[(i)]) >> (b[(i)]) >> (c[(i)])
#define matin(i,h,j,w,a) rep((i),(h)) rep((j),(w)) cin >> a[i][j]
#define e1 first
#define e2 second
#define ctol(c) ll((c)) - ll('0')
#define ltos(n) to_string((n))
#define items(kv, v) for(auto &(kv): (v))
#define ndig(N, n) ctol(ll(ltos((N))[ll(ltos((N)).length()) - (n)]))
#define beto(a,b,c) (a) < (b) && (b) < (c)
#define betc(a,b,c) (a) <= (b) && (b) <= (c) 
#define rsort(a,n) sort(a,a+n,greater<>())
#define Forchar(c,a,z) for(char (c) = (a); (c) <= (z); (c)++) 
#define cntchar(s,c) count(all((s)), c)
#define substring(s, start, end) s.substr((start), (end) - (start) + 1)
#define prl_nd(num, digits) cout << fixed << setprecision(digits) << (num) << endl;

const ll MAX_N = 100000;

int main(void){
    double x[3],y[3];
    rin2(i,3,x,y);

    double answer = 0;

    prl_nd(0.5 * abs((x[1] - x[0]) * (y[2] - y[0]) - (y[1] - y[0]) * (x[2] - x[0])), 4);
    
    return 0;
}

Submission

Task問題 C - 直訴
User nameユーザ名 nabenabe0928
Created time投稿日時
Language言語 C++14 (GCC 5.4.1)
Status状態 AC
Score得点 100
Source lengthソースコード長 4426 Byte
File nameファイル名
Exec time実行時間 1 ms
Memory usageメモリ使用量 256 KB

Test case

Set

Set name Score得点 / Max score Cases
all 100 / 100 00_sample_01.txt,00_sample_02.txt,00_sample_03.txt,test_01.txt,test_02.txt,test_03.txt,test_04.txt,test_05.txt,test_06.txt,test_07.txt,test_08.txt,test_09.txt,test_10.txt,test_11.txt,test_12.txt,test_13.txt,test_14.txt,test_15.txt,test_16.txt,test_17.txt,test_18.txt,test_19.txt,test_20.txt,test_21.txt,test_22.txt,test_23.txt,test_24.txt,test_25.txt,test_26.txt,test_27.txt,test_28.txt,test_29.txt,test_30.txt,test_31.txt,test_32.txt,test_33.txt,test_34.txt,test_35.txt,test_36.txt,test_37.txt,test_38.txt,test_39.txt,test_40.txt,test_41.txt,test_42.txt,test_43.txt,test_44.txt,test_45.txt,test_46.txt,test_47.txt,test_48.txt,test_49.txt,test_50.txt,test_51.txt,test_52.txt,test_53.txt,test_54.txt,test_55.txt,test_56.txt,test_57.txt,test_58.txt,test_59.txt,test_60.txt,test_61.txt,test_62.txt,test_63.txt,test_64.txt,test_65.txt,test_66.txt,test_67.txt,test_68.txt,test_69.txt

Test case

Case name Status状態 Exec time実行時間 Memory usageメモリ使用量
00_sample_01.txt AC 1 ms 256 KB
00_sample_02.txt AC 1 ms 256 KB
00_sample_03.txt AC 1 ms 256 KB
test_01.txt AC 1 ms 256 KB
test_02.txt AC 1 ms 256 KB
test_03.txt AC 1 ms 256 KB
test_04.txt AC 1 ms 256 KB
test_05.txt AC 1 ms 256 KB
test_06.txt AC 1 ms 256 KB
test_07.txt AC 1 ms 256 KB
test_08.txt AC 1 ms 256 KB
test_09.txt AC 1 ms 256 KB
test_10.txt AC 1 ms 256 KB
test_11.txt AC 1 ms 256 KB
test_12.txt AC 1 ms 256 KB
test_13.txt AC 1 ms 256 KB
test_14.txt AC 1 ms 256 KB
test_15.txt AC 1 ms 256 KB
test_16.txt AC 1 ms 256 KB
test_17.txt AC 1 ms 256 KB
test_18.txt AC 1 ms 256 KB
test_19.txt AC 1 ms 256 KB
test_20.txt AC 1 ms 256 KB
test_21.txt AC 1 ms 256 KB
test_22.txt AC 1 ms 256 KB
test_23.txt AC 1 ms 256 KB
test_24.txt AC 1 ms 256 KB
test_25.txt AC 1 ms 256 KB
test_26.txt AC 1 ms 256 KB
test_27.txt AC 1 ms 256 KB
test_28.txt AC 1 ms 256 KB
test_29.txt AC 1 ms 256 KB
test_30.txt AC 1 ms 256 KB
test_31.txt AC 1 ms 256 KB
test_32.txt AC 1 ms 256 KB
test_33.txt AC 1 ms 256 KB
test_34.txt AC 1 ms 256 KB
test_35.txt AC 1 ms 256 KB
test_36.txt AC 1 ms 256 KB
test_37.txt AC 1 ms 256 KB
test_38.txt AC 1 ms 256 KB
test_39.txt AC 1 ms 256 KB
test_40.txt AC 1 ms 256 KB
test_41.txt AC 1 ms 256 KB
test_42.txt AC 1 ms 256 KB
test_43.txt AC 1 ms 256 KB
test_44.txt AC 1 ms 256 KB
test_45.txt AC 1 ms 256 KB
test_46.txt AC 1 ms 256 KB
test_47.txt AC 1 ms 256 KB
test_48.txt AC 1 ms 256 KB
test_49.txt AC 1 ms 256 KB
test_50.txt AC 1 ms 256 KB
test_51.txt AC 1 ms 256 KB
test_52.txt AC 1 ms 256 KB
test_53.txt AC 1 ms 256 KB
test_54.txt AC 1 ms 256 KB
test_55.txt AC 1 ms 256 KB
test_56.txt AC 1 ms 256 KB
test_57.txt AC 1 ms 256 KB
test_58.txt AC 1 ms 256 KB
test_59.txt AC 1 ms 256 KB
test_60.txt AC 1 ms 256 KB
test_61.txt AC 1 ms 256 KB
test_62.txt AC 1 ms 256 KB
test_63.txt AC 1 ms 256 KB
test_64.txt AC 1 ms 256 KB
test_65.txt AC 1 ms 256 KB
test_66.txt AC 1 ms 256 KB
test_67.txt AC 1 ms 256 KB
test_68.txt AC 1 ms 256 KB
test_69.txt AC 1 ms 256 KB